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Home/ Questions/Q 8230877
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T17:16:53+00:00 2026-06-07T17:16:53+00:00

I have to write a method to sort both Integers and Doubles. public ArrayList<Number>

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I have to write a method to sort both Integers and Doubles.

public ArrayList<Number> sortDescending(ArrayList<Number> al){
    Comparator<Number> c=Collections.reverseOrder();
    Collections.sort(al,c);
    return al;
}

public ArrayList<Number> sortAscending(ArrayList<Number> al){
    Collections.sort(al);
    return al;
}

The problem is that in sortAscending, the following error occurs:

Bound mismatch: The generic method sort(List) of type Collections is not applicable for the arguments (ArrayList). The inferred type Number is not a valid substitute for the bounded parameter < T extends Comparable < ? super T>>

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T17:16:56+00:00Added an answer on June 7, 2026 at 5:16 pm

    You need to use a generic upper bound of Number intersecting with Comparable<T>:

    public <T extends Number & Comparable<T>> ArrayList<T> sortDescending(ArrayList<T> al){
        Comparator<T> c=Collections.reverseOrder();
        Collections.sort(al,c);
        return al;
    }
    
    public <T extends Number & Comparable<T>> ArrayList<T> sortAscending(ArrayList<T> al){
        Collections.sort(al);
        return al;
    }
    

    All JDK Numbers (eg Float, Integer etc) match this typing.

    For the uninitiated, the syntax <T extends A & B> is the way you bound T to both A and B.

    FYI, there is no syntax for “or” logic (nor would it make sense if you think about it)

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