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Asked: 2026-06-15T13:12:17+00:00

I have tried creating the following function: def 3utr(): do_something() . However, I get

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I have tried creating the following function:
def 3utr():
do_something().
However, I get a SyntaxError. Replacing the “3” by “three” fixes the problem.

My questions are:

  • Why is it a syntax error?
  • Is there a way to have a function name start with a number in Python 3?
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1 Answer

  1. Editorial Team

    It is a syntax error because the language specification does not allow identifiers to start with a digit. So it’s not possible to have function names (which are identifiers) that start with digits in Python.

    identifier ::= (letter|"_") (letter | digit | "_")*

    Python 2 Language Reference

    Within the ASCII range (U+0001..U+007F), the valid characters for identifiers are the same as in Python 2.x: the uppercase and lowercase letters A through Z, the underscore _ and, except for the first character, the digits 0 through 9.

    Python 3 Language Reference

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