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Home/ Questions/Q 7939605
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T23:09:10+00:00 2026-06-03T23:09:10+00:00

I have tried to split strings in JS like.. ‘a b c’ => [‘a’,’b’,’c’]

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I have tried to split strings in JS like..

'a b c' => ['a','b','c']
'a bb cc dd' => ['a','bb','cc','dd]
'a "bb cc" dd' => ['a','bb cc', 'dd']
"a 'bb cc' dd" => ['a','bb cc', 'dd']

How do I do it in JS regexp?
I have tried

/\w+|"(?:\\"|[^"])+"/g

but it returns…

'a b c' => ['a','b','c']
'a bb cc dd' => ['a','bb','cc','dd]
'a "bb cc" dd' => ['a','"bb cc"', 'dd']
"a 'bb cc' dd" => ['a','bb','cc', 'dd']
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T23:09:12+00:00Added an answer on June 3, 2026 at 11:09 pm

    Suppose you have a string:

    var s = "a b c 'd e f' g \"h i j\" k";
    

    You can quite easily match the tokens using:

    /"[^"]*"|'[^']*'|\S+/g
    

    That pattern:

    • Matches a string wrapped with double quotes, or…
    • Matches a string wrapped with single quotes, or…
    • Matches non-spaces.

    The result tokens, however, will be wrapped in quotes.
    Here is an example of a way to remove these quotes:

    var words = [];
    s.replace(/"([^"]*)"|'([^']*)'|(\S+)/g,
             function(g0,g1,g2,g3){
                  words.push(g1 || g2 || g3 || '');
             });
    

    This has a few tricks, but the idea is that we pick the group that isn’t empty (which is a falsey value is JavaScript). You could achieve the same with exec, but the code is messier in my opinion.

    Working example: http://jsfiddle.net/snS62/ (warning – alerts)

    To also allow escaped characters, you may use:

    /"([^\\"]*(?:\\.[^\\"]*)*)"|'([^\\']*(?:\\.[^\\']*)*)'|(\S+)/g
    
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