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Home/ Questions/Q 6646007
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:21:37+00:00 2026-05-26T00:21:37+00:00

I have two ArrayCollection and I want to merge them into one… arr1 =

  • 0

I have two ArrayCollection and I want to merge them into one…

arr1 = 
[0] -> month = 07
       tot_err = 15
[1] -> month = 08
       tot_err = 16
[2] -> month = 09
       tot_err = 17


arr2 = 
[0] -> month = 07
       tot_ok = 5
[1] -> month = 08
       tot_ok = 6
[2] -> month = 09
       tot_ok = 7

I would like to have this array

arr3 = 
[0] -> month = 07
       tot_err = 15
       tot_ok = 5
[1] -> month = 08
       tot_err = 16
       tot_ok = 6
[2] -> month = 09
       tot_err = 17
       tot_ok = 7    

How can I do it?

EDIT:

I did this solution:

        private function mergeArrays(a:ArrayCollection, b:ArrayCollection):ArrayCollection
        {
            for (var i:int=0;i<a.length;i++)
                for each(var item:Object in b)
                {                   
                    if( a[i].month == item.month){
                         a[i].tot_err = item.tot_err;
                    }
                }
            return a;
        }

But there is an important problem, if array2 (b) has a item.month that there isn’t in the array1 (a) the value is lost…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T00:21:38+00:00Added an answer on May 26, 2026 at 12:21 am
    private function mergeArrays(a:ArrayCollection, b:ArrayCollection):ArrayCollection
    {
        var result:ArrayCollection = new ArrayCollection();
        var months:Dictionary = new Dictionary();
        for (var i:int = 0; i < a.length; i++)
        {
            var mergedItem:Object = new Object();
            mergedItem.month = a[i].month;
            mergedItem.tot_ok = a[i].tot_ok;
            mergedItem.tot_err = null;
            for (var j:int = 0; j < b.length; j++)
            {                   
                if(a[i].month == b[j].month)
                {
                    mergedItem.tot_err = b[j].tot_err;
                }
            }
            month[mergedItem.month] = true;
            result.addItem(mergedItem);
        }
        // so far we have handled all occurrences between a and b,
        // now we need to handle the items from b that are left
        for each (var bItem:Object in b)
        {
            mergedItem = new Object();
            mergedItem.month = bItem.month;
            mergedItem.tot_err = bItem.tot_err;
            mergedItem.tot_ok = null;
            if (months[mergedItem.month] == null)
            {
                month[mergedItem.month] = true;
                result.addItem(mergedItem);
            }
        }
        return result;
    }
    
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