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Home/ Questions/Q 8178669
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T23:49:12+00:00 2026-06-06T23:49:12+00:00

I have two ArrayLists named ProductList and ItemList . ProductList holds two string[] arrays.

  • 0

I have two ArrayLists named ProductList and ItemList.

ProductList holds two string[] arrays.

string[0]    string[1]
---------   -----------
ProductID    ProductName
---------   -------------
  A001        Food
  B120        NotFood

ItemList holds three string[] arrays.

string[0]   string[1]    string[2]
---------  -----------  -----------
ProductID    ItemID       ItemName
---------  -----------  -----------
  A001       X12332        Rice
  A001       X2133         Pepsi
  A001       X12450        Sardine
  B120       H1LKL         Pen
  B120       JLA122        Printer

I want to show these data in a TreeView.

So I wrote the coding as shown below:

for(int i = 0; i <ProductList.Count; i++) //loop for every item in ProductList
{
    TreeNode node = new TreeNode(((string[])ProductList[i])[1]); //create Parent node using ProductName
    TreeView.Nodes.Add(node); //add node into TreeView
    for(int j = 0; j < ItemList.Count; i++) //loop for every item in ItemList
    {
         if(((string[])ProductList[i])[0] == ((string[])ItemList[j])[0]) //Compare if ProdutID in ProductList same with ProductID in ItemList
         {
             node.Nodes.Add(((string[])ItemList[j])[2]); //Add ItemName from ItemList as Child node for current Parent Node
         }
    }
}

Running the above code, I get the following result :

+Food
 - Rice
 - Pepsi
 - Sardine
+NotFood
 - Pen
 - Printer

Question:
How can I get the ItemID when user select the Node?

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T23:49:13+00:00Added an answer on June 6, 2026 at 11:49 pm

    Now, to the point of your question: TreeNode has two interesting properties, Name and Text. Text is what the user reads, and Name is an arbitrary, well, name. Maybe, when you are adding the items to the TreeView, you could set the ItemID as the Name of the TreeNode.

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