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Home/ Questions/Q 6992747
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T19:40:29+00:00 2026-05-27T19:40:29+00:00

I have two arrays: $array1 = array(‘[param1]’ ,’demo’ ,'[param2]’ ,’some’ ,'[param3]’); $array2 = array(‘value1’

  • 0

I have two arrays:

$array1 = array('[param1]' ,'demo' ,'[param2]' ,'some' ,'[param3]');
$array2 = array('value1'   ,'demo' ,'value2'   ,'some' ,'value3');

I want to compare these two arrays and remove all duplicate values.
In the end, I want these two arrays but without ‘demo’ and ‘some’ values in them.
I want to remove all values from arrays that have the same index key and value.
Arrays will always have the same number of values and indexes, I only want to compare them and remove entries that have the same index key and value, from both of them.

I’m doing something like this now:

$clean1 = array();
$clean2 = array();    

foreach($array1 as $key => $value)
{
    if($value !== $array2[$key])
    {
        $clean1[$key] = $value;
        $clean2[$key] = $array2[$key];
    }
}
    
var_export($clean1);
echo "<br />";
var_export($clean2);

And this works! But I’m wondering is there any other way of doing this? Maybe without using foreach loop?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T19:40:30+00:00Added an answer on May 27, 2026 at 7:40 pm
    array_unique( array_merge($arr_1, $arr_2) );
    

    or you can do:

    $arr_1_final = array_diff($arr_1, $arr_2);
    $arr_2_final = array_diff($arr_2, $arr_1);
    
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