I have two arrays that I want to loop in. I construct those properly and before going into for loop, I do echo them to be sure everything is ok with arrays.
But when I run the script, it outputs an error:
l<=: syntax error: operand expected (error token is "<="
I consulted the mighty Google and I understood it suffers from the lack of the second variable, but I mentioned earlier I do echo the values and everything seems to be OK. Here is the snippet..
#!/bin/bash
k=0
#this loop is just for being sure array is loaded
while [[ $k -le ${#hitEnd[@]} ]]
do
echo "hitEnd is: ${hitEnd[k]} and hitStart is: ${hitStart[k]}"
# here outputs the values correct
k=$((k+1))
done
k=0
for ((l=${hitStart[k]};l<=${hitEnd[k]};l++)) ; do //this is error line..
let array[l]++
k=$((k+1))
done
The variables in the for loop are echoed correctly but for loop won’t work.. where am I wrong?
#
as gniourf_gniourf answered:
“… At some point, k will reach the value ${#hitEnd[@]}, and this is
exactly when hitEnd[k] is not defined and expands to an empty string!
Bang!”
meaning error output is displayed not at the beginning of the loop, but when k has a greater value than array’s indices, pointing an index that array does not include…
That’s because at some point
${hitEnd[k]}expands to nothing (it is undefined). I get the same error with((l<=)). You should write yourforloop as:so as to always have an index
kthat corresponds to a defined field in the array${hitEnd[@]}.Also, instead of
you can just write
Done!
Your script revised using better modern bash practice:
Now, I’m not too sure the
forloop does exactly what you want it to… Don’t you mean this instead?