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Home/ Questions/Q 6539441
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T10:51:35+00:00 2026-05-25T10:51:35+00:00

I have two classes A and B while B is a subtype of A:

  • 0

I have two classes A and B while B is a subtype of A:

public class A {
    private String stringVar;

    public A()  {
        stringVar = "";
    }

    public String getStringVar() {
        return stringVar;
    }

    public void setStringVar(String str) {
        this.stringVar = str;
    }

    @Override 
    public String toString()  {
        return getStringVar();
    }
}

Class B:

public class B extends A {
    private int intVar;

    public B()  {
        intVar = 0;
    }

    public int getIntVar() {
        return intVar;
    }

    public void setIntVar(int intVar) {
        this.intVar = intVar;
    }

    @Override
    public String toString()  {
        return super.toString() + " " + getIntVar();
    }
}

As you can see in the following main method I assign the b to a. Now “a” can’t invoke b’s methods which is clear, because I’m using an instance of type A now. But it behaves like a B when toString is invoked. Curious, I would have expected toString of a. Why is this so?

public class Main {

    public static void main(String[] args) {
        A a = new A();
        B b = new B();
        b.setIntVar(200);
        b.setStringVar("foo");
        a = b;
        System.out.println(a);
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-25T10:51:35+00:00Added an answer on May 25, 2026 at 10:51 am

    This is nature of inheritance / polymorphism and overriding methods.

    Overrided methods will be determined in runtime based on objects real type and not based on reference type.

    Therefore a.toString() is actually b.toString() because it is determined in runtime.

    http://download.oracle.com/javase/tutorial/java/IandI/override.html

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