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Home/ Questions/Q 4044652
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T13:17:06+00:00 2026-05-20T13:17:06+00:00

I have two classes: class Object { public: Object(); virtual void update(); virtual void

  • 0

I have two classes:

class Object {
public:
  Object();
  virtual void update();
  virtual void draw();

private:

protected:
  int x, y, tick;

}

and

class Unit : public Object {
public:
  Unit();
  void update();

private:

protected:

}

I then define the constructors and functions in sepparate .cpp files.

Here’s the definitions for Object:

Object::Object() {
  x = y = 0;
};

Object::update() {
  tick ++;
};

Object::draw() {
  // All my draw code is in here.
};

And Unit:

Unit::Unit() : Object() {

};

Unit::update() {
  Object::update();
  // Then there's a bunch of movement related code here.
};

Everything works fine individually, but I run into a problem when trying to call functions from within a vector.

vector<Object> objects;

I then do this in my void main():

for (int i = 0; i < objects.size(); i ++) {
  objects[i].update();
  objects[i].draw();
};

This draws everything fine, but it only calls the Object verson of update() not the version as defined by the derived class. Do I have to make a vector for each type that I derive from the Object class for it to work, or is there another way to call the derived functions?

Thanks in advance – Seymore

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T13:17:08+00:00Added an answer on May 20, 2026 at 1:17 pm

    Yes, it calls methods of class Object, because you have a vector of class Object objects:

    vector<Object> objects; // stores instances of class Object
    

    The possible solution is to use a vector of pointers:

    vector<Object*> objects;
    objects.push_back( new Unit() );
    

    and then call though pointers:

    for (int i = 0; i < objects.size(); i ++) {
        objects[i]->update();
        objects[i]->draw();
    }
    
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