Question

I have two data.frames each with three columns: chrom, start & stop, let’s call them rangesA and rangesB. For each row of rangesA, I’m looking to find which (if any) row in rangesB fully contains the rangesA row – by which I mean rangesAChrom == rangesBChrom, rangesAStart >= rangesBStart and rangesAStop <= rangesBStop.

Right now I’m doing the following, which I just don’t like very much. Note that I’m looping over the rows of rangesA for other reasons, but none of those reasons are likely to be a big deal, it just ends up making things more readable given this particular solution.

rangesA:

chrom   start   stop
 5       100     105
 1       200     250
 9       275     300

rangesB:

chrom    start    stop
  1       200      265
  5       99       106
  9       275      290

for each row in rangesA:

matches <- which((rangesB[,'chrom']  == rangesA[row,'chrom']) &&
                 (rangesB[,'start'] <= rangesA[row, 'start']) &&
                 (rangesB[,'stop'] >= rangesA[row, 'stop']))

I figure there’s got to be a better (and by better, I mean faster over large instances of rangesA and rangesB) way to do this than looping over this construct. Any ideas?

Answer 1

This would be a lot easier / faster if you can merge the two objects first.

ranges <- merge(rangesA,rangesB,by="chrom",suffixes=c("A","B"))
ranges[with(ranges, startB <= startA & stopB >= stopA),]
#  chrom startA stopA startB stopB
#1     1    200   250    200   265
#2     5    100   105     99   106