Question

I have two databases in same server with same username and pass. Right now I am connecting to only one database, but I would like to connect to both.

For now this is my code, whick connect only to one database:

connect1.php

<?
$servername='localhost';

$dbusername='user';
$dbpassword='pass';

$dbname1='db1';
$dbname2='db2';

$link1 = connecttodb($servername,$dbname1,$dbusername,$dbpassword);
$link2 = connecttodb($servername,$dbname2,$dbusername,$dbpassword);

function connecttodb($servername,$dbname,$dbusername,$dbpassword)
{
    $link=mysql_connect ("$servername","$dbusername","$dbpassword",TRUE);
    if(!$link){die("Could not connect to MySQL");}
    mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());
    return $link;
}
    ?>

I display result in result.php with this code:

<?
require "connect1.php"; 

$q=mysql_query("select * from table1 where username='test' order by id",link1);

while($nt=mysql_fetch_array($q)){
echo "$nt[location]";
}

?>

I would like to display similar data in result.php, but with connection to db2

How can I do that? Thank you!

Answer 1

Instead of having a single global $link variable, you need two:

$link1 = connecttodb($servername1,$dbname1,$dbusername1,$dbpassword1);
$link2 = connecttodb($servername2,$dbname2,$dbusername2,$dbpassword2);

And of course change connectodb() to:

function connecttodb($servername,$dbname,$dbuser,$dbpassword)
{
    $link=mysql_connect ("$servername","$dbuser","$dbpassword",TRUE);
    if(!$link){die("Could not connect to MySQL");}
    mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());
    return $link;
}

Please note that i’ve added a fourth parameter to mysql_connect, stating TRUE for the new_link parameter (this will only be needed if the two databases reside on the same server).

Then, for each query you will have to specify the corresponding link variable (either $link1 or $link2) according to the database you wish to query.