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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:02:28+00:00 2026-05-11T21:02:28+00:00

I have two elements that shouldn’t be active at the same time, so when

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I have two elements that shouldn’t be active at the same time, so when one is toggled I fade the other out, however I would like to be able to fade the open element out and then bring the other one in. Is there a way to do this that isn’t a hack?

<script ="text/javascript">

$(function() {
    $('#jlogin').click(function() {
        $('#login').toggle('fast');
        $('#reg').fadeOut('fast');
    });

    $('#jreg').click(function() {
        $('#reg').toggle('fast');
        $('#login').fadeOut('fast');
    });
});

</script>

That is my current script.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:02:29+00:00Added an answer on May 11, 2026 at 9:02 pm

    Look at using the callback mechanism for fadeOut so you can chain the animations. The callback on the animation methods are called after the previous animation is complete.

     <script type="text/javascript">
        $(function() {
            $('#jlogin').click(function() {
               $('#reg').fadeOut('fast', function() {
                   $('#login').toggle('fast');
               });
            });
            $('#jreg').click(function() {
                $('#login').fadeOut( 'fast', function() {
                    $('#reg').toggle('fast');
                });
            });
         });
    </script>
    
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