Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 873317
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T10:54:54+00:00 2026-05-15T10:54:54+00:00

I have two EmailAddress generic lists, I wanted a simple way of just getting

  • 0

I have two EmailAddress generic lists, I wanted a simple way of just getting all the EmailAddress objects that are in List1 that aren’t in List2.

I’m thinking a left outer join of some sort with Linq but I’m a little confused on how to set that up. I’m open to a better solution as well.

Update: I should have noted these are custom data type lists of my “EmailAddress” objects.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T10:54:55+00:00Added an answer on May 15, 2026 at 10:54 am

    Most of these answers will not work since the items in List1 and List2 may be equal in the eyes of the user, but are actually references to different instances (they are not reference equal).

    Assuming Address is a string property of EmailAddress, here’s a left join solution.

    IEnumerable<EmailAddress> query = 
      from a1 in list1
      join a2 in list2 on a1.Address equals a2.Address into g
      from x in g.DefaultIfEmpty()
      where x == null
      select a1;
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

We have two mailing lists that we need to combine, and then make sure
I have two queries that find both the Zip codes, and the States for
I have two regular expressions for one user input field that should accept a
I have two form elements on my page that act as a smooth login
I have two long list, one from a log file that contains lines formatted
I have two tables with a Many-To-Many relationship like this: User( emailaddress , Name)
I just started using gApps scripts and I have run into two problems with
I am going to make this REALLY simple. I have two tables. public class
I have a web service with a method that has two string parameters. When
I have a form that needs to be submitted to two separate URLs: one

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.