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Home/ Questions/Q 6667739
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:57:55+00:00 2026-05-26T02:57:55+00:00

I have two entities in my domain model: public class Configuration : DomainEntity {

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I have two entities in my domain model:

public class Configuration : DomainEntity
   {        
        public virtual ICollection<Hardware> Hardwares { get; set; }
        public Configuration()
        {
            Hardwares = new List<Hardware>();
        }
   }
public class Hardware : DomainEntity
    {
        public virtual ICollection<Configuration> Configurations { get; set; }
        public Hardware()
        {
            Configurations = new HashSet<Configuration>();
        }
   }

And I have three tables in database. I bind these tables:
enter image description here

modelBuilder.Entity<Configuration>().
    HasMany<Hardware>(configuration => configuration.Hardwares).
    WithMany(hardware => hardware.Configurations).
    Map(map => map.ToTable("tblConfiguration_Hardware"));

And it work fine, but… When I add the same hardwares, for example three hardwares, I get one record in database.

   Hardware hardware = db.Find<Hardware>(hardwareID);
   configuration.Hardwares.Add(hardware);  // first
   configuration.Hardwares.Add(hardware);  // second
   configuration.Hardwares.Add(hardware);  // third
   db.Add<Configuration>(configuration);
   db.SaveChanges();

But I want to save three relations. What do i wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:57:55+00:00Added an answer on May 26, 2026 at 2:57 am

    You cannot do that with many-to-many relation. You must model your Configuration_Hardware as separate entity with one-to-many relations to Configuration and Hardware.

    The reason why it doesn’t work is that many-to-many relation with hidden junction table expects that FKs used in junction table forms complex PK but in your case you have separate PK and so you must map it as separate entity.

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