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Home/ Questions/Q 7186859
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T18:43:17+00:00 2026-05-28T18:43:17+00:00

I have two files. In the first there is a dictionary ready for export:

  • 0

I have two files. In the first there is a dictionary ready for export:

__all__ = ['container']

def show_name(self):
   myFunction()
   print self.name

container = {
   'show_name': show_name
}

In the second file I import myFunction and I define the class Person:

from myModule import myFunction

class Person:
   def __init__(self):
      self.name = 'Bob'
      self.show_name = types.MethodType(container['show_name'], self)

person = Person()

The problem is that when I call person.show_name() I get the error:

NameError: global name ‘myFunction’ is not defined

How can I have Person.show_name access the same functions Person does?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T18:43:18+00:00Added an answer on May 28, 2026 at 6:43 pm

    Move from myModule import myFunction to the same file where show_name is defined.


    By the way,

    class Person:
       def __init__(self):
          self.name = 'Bob'
          self.show_name = types.MethodType(container['show_name'], self)
    

    makes ('show_name',<bound_method>) a key-value pair in self.__dict__. That causes every instance of Person to get a new, independent key-value pair.

    To save memory, you might want to change that to Roman Bodnarchuk other solution.

    class Person:
       show_name = container['show_name']
       def __init__(self):
          self.name = 'Bob'
    
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