Question

I have two forms: Form1 and Form2.

I want to show Form2 as dialog when Form1 has been loaded. I mean when Form1 is loaded and visible to the user, then Form2 is showed as dialog.

With the Form1_Load event it first show the Form2 as dialog and then show Form1.

How can I first show Form1 and then Form2 as dialog?

Answer 1

Use the Shown event of form1 to load the form2 as follows:

void form1_Shown(object sender, EventArgs e)
{
    Form2 form2 = new Form2();
    form2.Show();
}

That way first form1 will be displayed and raise the Shown event and inside Shown event, form2 will be loaded and displayed.