Question

I have Two forms in my index.php and am trying to get them to submit and POST their data seperatly

Form 1

echo '<form action="process.php?type=news" method="post">';
echo '<table cellspacing="0"><tr><th>';
echo 'Add News to News Feed';
echo '</th></tr><tr><td>';
echo 'Title:<br /><input name="newstitle" type="text" id="add" style="height:16px;width:525px;" size="80" maxlength="186" /><br />';
echo 'Main Body Text:<br /><textarea name="newsfeed" id="add" style="width:525px;height:78px;" maxlength="2000" ></textarea>';
echo '<input style="float:right;margin-top:5px;" id="button" type="submit" value="Submit" />';
echo '</td></tr></table></from>';

And Form 2

echo '<form action="process.php?type=suggest" method="post">';
echo '<table cellspacing="0"><tr><th>';
echo 'Suggest Additions to the Intranet';
echo '</th></tr><tr><td>';
echo '<textarea name="suggest" id="add" style="width:330px;height:60px;" maxlength="800" ></textarea>';
echo '<input style="float:right;margin-top:5px;" id="button" type="submit" value="Submit" />';
echo '</td></tr></table></from>';

I want these both to post and do the action after pressing the submit button, but currently the second form submit to the first forms action

How can i fix this???

EDIT: Also i am using .PHP for both the index and process page then using it to echo the forms onto the page

Also here is the process.php data

$type=$_REQUEST['type'];
$suggest=$_POST['suggest'];
$newstitle=$_POST['newstitle'];
$news=mysql_real_escape_string($_POST['newsfeed']);

if ($type == "news")
{
  $sql=mysql_query("SELECT * FROM newsfeed WHERE title = ('$newstitle')");
  $number_of_rows = mysql_num_rows($sql);
  if ($number_of_rows > 0)
  {
    echo 'This Title is Already Taken';
  }
  else
  {
    $sql="INSERT INTO newsfeed (title, news) VALUES ('$newstitle','$news')";    
    if (!mysql_query($sql,$con))
    {
      die('Error: ' . mysql_error());
    }
    header('Location: index.php');
    exit;
  }
}
elseif ($type == "suggest")
{
  $sql="INSERT INTO suggestions VALUES ('$suggest')";
  if (!mysql_query($sql,$con))
  {
    die('Error: ' . mysql_error());
  }
  header('Location: index.php');
  exit;
}

Answer 1

Could it be that you are not closing the form with </form>, but with </from>, so the code of the second form is in fact still inside the first form since the tags are never closed?