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Home/ Questions/Q 737841
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:46:05+00:00 2026-05-14T07:46:05+00:00

I have two forms. The first form is the mainForm, this never goes anywhere.

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I have two forms.
The first form is the mainForm, this never goes anywhere.
On opening the second form (saveForm), it will display over the top.
When i close this form, I want a certain piece of code in the mainForm to run.
I assume this is the correct way to get this to happen?

The code on saveForm when I close and return to the mainForm:

private void btnSaveDetails_Click(object sender, EventArgs e)
    {
        Delivery d = new Delivery(txtNameBox.Text, txtAddressBox.Text, txtDayBox.Text, txtTimeBox.Text, txtMealBox.Text, txtInstructionsBox.Text, txtStatusBox.Text);
        mainForm.myDeliveries.Add(d);
        this.Close();
    }

Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:46:05+00:00Added an answer on May 14, 2026 at 7:46 am

    You have to set the DialogResult property of you dialog form. Either explicitly in code or by assingning the dialog result to a button on your form.

    private void btnSaveDetails_Click(object sender, EventArgs e)
    {
        Delivery d = new Delivery(
            txtNameBox.Text, txtAddressBox.Text, txtDayBox.Text,  
            txtTimeBox.Text, txtMealBox.Text, txtInstructionsBox.Text, 
            txtStatusBox.Text
        );
        mainForm.myDeliveries.Add(d);
        this.DialogResult = DialogResults.OK;
    }
    

    No need to call Close() setting this.DialogResult does that for you if you called the dialog using ShowDialog().

    On calling the form you have to do the following:

    var frm = new MyForm();
    if (frm.ShowDialog() == DialogResults.OK) {
         // do what you want to do on success.
    }
    
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