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Home/ Questions/Q 6871397
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:48:04+00:00 2026-05-27T03:48:04+00:00

I have two lists see below…..result is coming back as empty List<Pay>olist = new

  • 0

I have two lists see below…..result is coming back as empty

List<Pay>olist = new List<Pay>();
List<Pay> nlist = new List<Pay>();
Pay oldpay = new Pay()
{
    EventId = 1,
    Number = 123,                        
    Amount = 1
};

olist.Add(oldpay);
Pay newpay = new Pay ()
{
   EventId = 1,
    Number = 123,                        
    Amount = 100
};
nlist.Add(newpay);
var Result = nlist.Intersect(olist);

any clue why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:48:04+00:00Added an answer on May 27, 2026 at 3:48 am

    You need to override the Equals and GetHashCode methods in your Pay class, otherwise Intersect doesn’t know when 2 instances are considered equal. How could it guess that it is the EventId that determines equality? oldPay and newPay are different instances, so by default they’re not considered equal.

    You can override the methods in Pay like this:

    public override int GetHashCode()
    {
        return this.EventId;
    }
    
    public override bool Equals(object other)
    {
        if (other is Pay)
            return ((Pay)other).EventId == this.EventId;
        return false;
    }
    

    Another option is to implement an IEqualityComparer<Pay> and pass it as a parameter to Intersect:

    public class PayComparer : IEqualityComparer<Pay>
    {
        public bool Equals(Pay x, Pay y)
        {
            if (x == y) // same instance or both null
                return true;
            if (x == null || y == null) // either one is null but not both
                return false;
    
            return x.EventId == y.EventId;
        }
    
    
        public int GetHashCode(Pay pay)
        {
            return pay != null ? pay.EventId : 0;
        }
    }
    
    ...
    
    var Result = nlist.Intersect(olist, new PayComparer());
    
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