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Home/ Questions/Q 9227301
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T05:02:22+00:00 2026-06-18T05:02:22+00:00

I have two methods like this HashSet<Tuple<int,int>> _xyPairs = new HashSet<Tuple<int,int>>(); private void SetTravelled(int

  • 0

I have two methods like this

HashSet<Tuple<int,int>> _xyPairs = new HashSet<Tuple<int,int>>();
private void SetTravelled(int x, int y, bool travelled)
{
    var t = new Tuple<int, int>(x, y);

    if (travelled)
        _xyPairs.Add(t);
    else
        _xyPairs.Remove(t);
}

private bool HaveTravelled(int x, int y)
{
    return _xyPairs.Contains(new Tuple<int, int>(x, y));
}

I don’t mind the first method so much because it’s not called very often. The second method however is called very frequently. So I have to create new Tuple’s over and over.

Is there a way to combine the two integers into one value for the Hashset?

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  1. Editorial Team
    Editorial Team
    2026-06-18T05:02:24+00:00Added an answer on June 18, 2026 at 5:02 am

    If you have an indication that the tuple is actually causing you a problem, you could try to combine the two 32-bit integers into one 64-bit integer:

    HashSet<long> _xyPairs = new HashSet<long>();
    
    private void SetTravelled(int x, int y, bool travelled)
    {
        var t = Combine(x, y)
        ...
    
    private bool HaveTravelled(int x, int y)
    {
        return _xyPairs.Contains(Combine(x, y));
    }
    
    private static long Combine(int x, int y)
    {
        return (long)(((ulong)x) | ((ulong)y) << 32);
    }
    
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