Question

I have two MySQL tables: house and features. This is for a real estate website.

house has this structure:

id | address | ... some other fields

features has this structure:

id | house_id | feature | value

as you can guess, a house can have multiple features, so a 1:n relationship exists.

Now, I’m implementing a search form for houses. I need to filter the results based on the features selected by the user.

Sample scenario: get all houses which have the features garage and garden, and a list of features in those houses.

What would be the best query to suit my needs? I’m not familiar with JOIN operations, so I need your help!

(OPTIONAL) If you can provide a Yii Framework-specific solution, it would be awesome 🙂

Answer 1

SELECT * 
FROM HOUSE H JOIN FEATURES F ON H.HOUSE_ID = F.HOUSE_ID
WHERE FEATURE IN ('GARDEN','GARAGE');