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Home/ Questions/Q 6663979
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:33:33+00:00 2026-05-26T02:33:33+00:00

I have two MySql tables like the following: Cat —— id : INT NOT

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I have two MySql tables like the following:

Cat
------
id : INT NOT NULL PRIMARY KEY
name : VARCHAR(32)

Cheezburger
-------
id : INT NOT NULL PRIMARY KEY
catId : INT FOREIGN KEY REFERENCES Cat (id)
pattyCount : INT

When I perform a LEFT JOIN on the two tables using PHP’s PDO I’d do the following:

$database = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $pasword);
$query = $database->prepare('
    SELECT * FROM Cat
    LEFT JOIN Cheezebuger.id ON Cheezburger.catId = cat.id
    WHERE Cat.id = ?');
$query->bindParam(1, $someId);
$query->execute();
$cat = $query-fetch();

My question is, how can I differentiate the id field associated with the Cat table and the id associated with the Cheezburger table? $cat['id'] is giving me the Cheezburger id field.

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:33:33+00:00Added an answer on May 26, 2026 at 2:33 am

    It’s often inadvisable to SELECT *. Instead, be explicit about the columns you want and assign aliases to like-named columns:

    SELECT
      Cat.id AS catid,
      Cat.name AS name,
      Cheezeburger.id AS chzid,
      ...
    FROM 
      Cat LEFT JOIN Cheezebuger.id ON Cheezburger.catId = cat.id
    WHERE Cat.id = ?
    

    Now, to retrieve Cat.id, use $cat['catid'] and to retrieve Cheezeburger.id, use $cat['chzid'].

    A strong reason against doing SELECT * is that if you add more columns later which are not needed in this particular part of your application, you won’t be using extra memory on the database server to retrieve unneeded data and fetch it into the web application where it won’t be used. If you happened to add a binary BLOB column later, you could potentially pull over a lot more data unnecessarily.

    The other reason is the one you’ve discovered. You can invite ambiguity in column names.

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