Question

I have two NSArrays that I’m comparing — in the NSLog output they look identical, yet they don’t equal each other somehow. If I convert the NSArray to an NSString I get the same exact result. Comparing them to themselves will be equal. How can I determine why one and two aren’t equal? thank you.

- (void)confused:(NSArray *)two {

    NSArray *one = [NSArray arrayWithObjects:@"16777223", @"7", nil];
    NSArray *two = [[NSBundle bundleWithPath:@"/path/to/bundle"] executableArchitectures];

    // NSArray "two" shows as 16277223, 7 in NSLog

    if ([two firstObjectCommonWithArray:(NSArray *)one])
    {
        NSLog(@"- it's equal %@ %@", one, two);
        // if array one matches array two then this will output
    }
    else {
        NSLog(@"- it's NOT equal %@ %@", one, two);
    }

    return;
}

Here’s the output from console:

myApp (
    16777223,
    7
)
myApp (
    16777223,
    7
)
myApp - it's NOT equal (
    16777223,
    7
)(
    16777223,
    7
)

Answer 1

-[NSBundle executableArchitectures] returns an array of NSNumber objects, not NSString objects, so the array you’re passing in doesn’t have strings in it. If you change

NSArray *one = [NSArray arrayWithObjects:@"16777223",@"7", nil];

to

NSArray *one = [NSArray arrayWithObjects:[NSNumber numberWithUnsignedInteger:NSBundleExecutableArchitectureX86_64], 
                                         [NSNumber numberWithUnsignedInteger:NSBundleExecutableArchitectureI386], 
                  nil];

your code should work.