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Home/ Questions/Q 9003839
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T00:45:46+00:00 2026-06-16T00:45:46+00:00

I have two pandas dataframes one called orders and another one called daily_prices .

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I have two pandas dataframes one called orders and another one called daily_prices.
daily_prices is as follows:

              AAPL    GOOG     IBM    XOM
2011-01-10  339.44  614.21  142.78  71.57
2011-01-13  342.64  616.69  143.92  73.08
2011-01-26  340.82  616.50  155.74  75.89
2011-02-02  341.29  612.00  157.93  79.46
2011-02-10  351.42  616.44  159.32  79.68
2011-03-03  356.40  609.56  158.73  82.19
2011-05-03  345.14  533.89  167.84  82.00
2011-06-03  340.42  523.08  160.97  78.19
2011-06-10  323.03  509.51  159.14  76.84
2011-08-01  393.26  606.77  176.28  76.67
2011-12-20  392.46  630.37  184.14  79.97

orders is as follows:

           direction  size ticker  prices
2011-01-10       Buy  1500   AAPL  339.44
2011-01-13      Sell  1500   AAPL  342.64
2011-01-13       Buy  4000    IBM  143.92
2011-01-26       Buy  1000   GOOG  616.50
2011-02-02      Sell  4000    XOM   79.46
2011-02-10       Buy  4000    XOM   79.68
2011-03-03      Sell  1000   GOOG  609.56
2011-03-03      Sell  2200    IBM  158.73
2011-06-03      Sell  3300    IBM  160.97
2011-05-03       Buy  1500    IBM  167.84
2011-06-10       Buy  1200   AAPL  323.03
2011-08-01       Buy    55   GOOG  606.77
2011-08-01      Sell    55   GOOG  606.77
2011-12-20      Sell  1200   AAPL  392.46

Index of both dataframes is datetime.date.
prices column in the orders dataframe was added by using a list comprehension to loop through all the orders and look up the specific ticker for the specific date in the daily_prices data frame and then adding that list as a column to the orders dataframe. I would like to do this using an array operation rather than something that loops. can it be done? I tried to use:

daily_prices.ix[dates, tickers] 

but this returns a matrix of cartesian product of the two lists. I want it to return a column vector of only the price of a specified ticker for a specified date.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T00:45:47+00:00Added an answer on June 16, 2026 at 12:45 am

    Use our friend lookup, designed precisely for this purpose:

    In [17]: prices
    Out[17]: 
                  AAPL    GOOG     IBM    XOM
    2011-01-10  339.44  614.21  142.78  71.57
    2011-01-13  342.64  616.69  143.92  73.08
    2011-01-26  340.82  616.50  155.74  75.89
    2011-02-02  341.29  612.00  157.93  79.46
    2011-02-10  351.42  616.44  159.32  79.68
    2011-03-03  356.40  609.56  158.73  82.19
    2011-05-03  345.14  533.89  167.84  82.00
    2011-06-03  340.42  523.08  160.97  78.19
    2011-06-10  323.03  509.51  159.14  76.84
    2011-08-01  393.26  606.77  176.28  76.67
    2011-12-20  392.46  630.37  184.14  79.97
    
    In [18]: orders
    Out[18]: 
                      Date direction  size ticker  prices
    0  2011-01-10 00:00:00       Buy  1500   AAPL  339.44
    1  2011-01-13 00:00:00      Sell  1500   AAPL  342.64
    2  2011-01-13 00:00:00       Buy  4000    IBM  143.92
    3  2011-01-26 00:00:00       Buy  1000   GOOG  616.50
    4  2011-02-02 00:00:00      Sell  4000    XOM   79.46
    5  2011-02-10 00:00:00       Buy  4000    XOM   79.68
    6  2011-03-03 00:00:00      Sell  1000   GOOG  609.56
    7  2011-03-03 00:00:00      Sell  2200    IBM  158.73
    8  2011-06-03 00:00:00      Sell  3300    IBM  160.97
    9  2011-05-03 00:00:00       Buy  1500    IBM  167.84
    10 2011-06-10 00:00:00       Buy  1200   AAPL  323.03
    11 2011-08-01 00:00:00       Buy    55   GOOG  606.77
    12 2011-08-01 00:00:00      Sell    55   GOOG  606.77
    13 2011-12-20 00:00:00      Sell  1200   AAPL  392.46
    
    In [19]: prices.lookup(orders.Date, orders.ticker)
    Out[19]: 
    array([ 339.44,  342.64,  143.92,  616.5 ,   79.46,   79.68,  609.56,
            158.73,  160.97,  167.84,  323.03,  606.77,  606.77,  392.46])
    
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