Question

I have two positions on a 3D system, say [15, 32, 42] and [16, 32, 42]

Is there a easy way to check if they are within a 1 block radius from each other?

This is what I have, but is there a better way of doing it:

if (pos[0] == pos1[0] / 32 || pos[0] == pos1[0] + 1 || pos[0] == pos1[0] - 1)
{
    if (pos[1] == pos1[1] || pos[1] == pos1[1] - 1 || pos[1] == pos1[1] + 1)
    {
        if (pos[2] == pos1[2] || pos[2] == pos1[2] + 1 || pos[2] == pos1[2] - 1)
        {

Thanks,
David

Answer 1

You can use Math.abs(pos[0]-pos1[0]) <= 1 to check if two coordinates in the same plane are at most 1 apart.

So all in all, your code could look like this:

if( Math.abs(pos[0]-pos1[0]) <= 1 
    && Math.abs(pos[1]-pos1[1]) <= 1 
    && Math.abs(pos[2]-pos1[2]) <= 1 )
{
  Within a 1 block radius
}

Note that I do not understand why you divided your first equation by 32. I did not include that in this answer.

Note also that this solution makes things a little more readable, but that yours is correct too.