Question

I have two programs,

Program A is like this,

int main(int argc, char** argv) {

    char* s = "hello";

    printf(s);

    return (EXIT_SUCCESS);
}

The base address of s is 0x80484e0 “hello”, Now I have Program B, as below

int main(int argc, char** argv) {

    void* p = (void*)0x80484e0;

    char* c = (char*)p;

    while(*c)
    {
        printf("%c",*c);
        c++;
    }

    return (EXIT_SUCCESS);
}

In program B ‘p’ is pointing to the same base address as ‘s’ in Program B but the contents are not same.

Even though ‘p’ and ‘s’ are having same base address their contents are not same, is it because they are running as different programs in different address space?

Answer 1

In program B ‘p’ is pointing to the same base address as ‘s’ in
Program B but the contents are not same.

That’s the magic of virtual addresses and separate address spaces. You need to look into “shared memory” for your platform.

Addresses used by a program are virtual. They’re not the same as the physical address in RAM. The kernel does some nice (nasty) stuff with the help of the MMU and a page table and hides this from the process.

So for example on a 32b system a process thinks it’s the sole user of the memory – it can use addresses from 0 to 0xffffffff – with certain restrictions.

If you happen to be on a POSIX system, you can look into mmap and shm_open.