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Home/ Questions/Q 6131815
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T17:01:29+00:00 2026-05-23T17:01:29+00:00

I have two questions regarding the behavior of running the below code. Why is

  • 0

I have two questions regarding the behavior of running the below code. Why is __new__ even being called without instantiating an object? I thought __new__ controlled the creation of a new instance. Next, why does delattr raise an AttributeError when hasattr returns True for size?

class ShapeBase(type):

  def __new__(cls, name, bases, attrs):
    rv = super(ShapeBase, cls).__new__(cls, name, bases, attrs)
    parents = [base for base in bases if isinstance(base, ShapeBase)]

    # don't do anything unless this is a subclass of Shape
    if not parents:
      return rv

    print hasattr(rv, 'altitude') # prints True
    print rv.altitude             # prints 7
    del rv.altitude               # deletes altitude from rv

    print hasattr(rv, 'size')     # prints True
    print rv.size                 # prints 5
    delattr(rv, 'size')           # raises AttributeError                    

    return rv

class Shape(object):
  __metaclass__ = ShapeBase
  size = 5

class Triangle(Shape):
  altitude = 7
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  1. Editorial Team
    Editorial Team
    2026-05-23T17:01:30+00:00Added an answer on May 23, 2026 at 5:01 pm

    For the second question delattr(rv, 'size') (and del rv.size) is failing because the attribute size is a class attribute not an instance attribute which mean is part of the class __dict__ not the instance __dict__.

    And the hasattr normally will return True because it search for an attribute in all the parent classes of the object passed to it.

    As for why your metaclass __new__ is called when the class body is evaluated think of it like this :

    If you create an instance of a class the class __new__ will be called when you create the instance, yes ? so the same should apply on class , a metaclass is a class of a class so the __new__ will be called when you create the class.

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