Question

I have two seperate tables in my DB, here the relevant fields:

table images:

CREATE TABLE `images` (
  `image_id` int(4) NOT NULL AUTO_INCREMENT,
  `project_id` int(4) NOT NULL,
  `user_id` int(4) NOT NULL,
  `image_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `image_description` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `date_created` date NOT NULL,
  `link_to_file` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `link_to_thumbnail` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `given_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `note` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  PRIMARY KEY (`image_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=51 ;

and table projects:

CREATE TABLE `projects` (
  `project_id` int(4) NOT NULL AUTO_INCREMENT,
  `user_id` int(4) NOT NULL,
  `project_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `project_description` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `date_created` date NOT NULL,
  `date_last_edited` date NOT NULL,
  `shared` int(1) NOT NULL,
  `password` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  PRIMARY KEY (`project_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=25 ;

I would like to display in a variable $content, a gallery of the oldest image from each project as a link to that project page and I have no idea how the mysql query should be built. Can you please help me with this? I have tried several if and while statements but the results have been complete failures and i am at the end of my (very limited) knowledge. I’m about to jump out the window…

So I would like to end up with

<a href="index.php?page=projects&id='.$projectid.'">
  <img src="oldest_photo_of_project_x" />
</a>
<a href="index.php?page=projects&id='.$projectid.'">
  <img src="oldest_photo_of_project_y" />
</a>
<a href="index.php?page=projects&id='.$projectid.'">
  <img src="oldest_photo_of_project_z" />
</a>

Update1:

To clarify I am trying to combine:

"SELECT * FROM projects WHERE user_id='$UserID' ORDER BY project_id DESC"

And maybe something like this:

$query = "SELECT images.project_id, projects.project_name ". 
"FROM images, projects ".
"WHERE images.project_id = projects.project_id";

Answer 1

Haven’t tested for errors, but I’d do something like this:

$result = mysql_query("SELECT DISTINCT 
    `projects`.`project_id` AS `project`, 
    `images`.`link_to_file` AS `filepath`
FROM 
    `projects`,
    `images`
WHERE 
    `projects`.`project_id` = `images`.`project_id`
ORDER BY 
    `images`.`date_created` DESC");

while ($resultLoop = mysql_fetch_array($result)) {
    $str .= '<a href="index.php?page=projects&id=' . $resultLoop["project"] . '">
        <img src="' . $resultLoop["filepath"] . '" />
    </a>';
}


echo $str;