I have two *.sql files that I use when creating a new web site database. The first file creates all the tables. The second file populates some default records. I would like to execute these files from PHP. I also use the Zend_Framework, if that will help accomplish this.
Additional Info
- I don’t have console access
- I’m trying to automate site generation from within our application.
SOLUTION
Using shell_exec()…
$command = 'mysql'
. ' --host=' . $vals['db_host']
. ' --user=' . $vals['db_user']
. ' --password=' . $vals['db_pass']
. ' --database=' . $vals['db_name']
. ' --execute="SOURCE ' . $script_path
;
$output1 = shell_exec($command . '/site_db.sql"');
$output2 = shell_exec($command . '/site_structure.sql"');
…I never did get useful output, but followed some suggestions on another thread and finally got it all working. I switch to the --option=value format for the commands and used --execute="SOURCE ..." instead of < to execute the file.
Also, I never got a good explanation of the difference between shell_exec() and exec().
This question comes up from time to time. There’s no good solution for running a .sql script directly from PHP. There are edge cases where statements common in a .sql script can’t be executed as SQL statements. For example, the mysql tool has builtin commands that are not recognized by the MySQL Server, e.g.
CONNECT,TEE,STATUS, andDELIMITER.So I give +1 to @Ignacio Vazquez-Abrams’s answer. You should run your .sql script in PHP by invoking the
mysqltool, for instance withshell_exec().I got this test working:
See also my answers to these related questions: