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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:36:46+00:00 2026-05-13T06:36:46+00:00

I have two structure in c struct data{ char *name; }; struct lst{ struct

  • 0

I have two structure in c

struct data{
  char *name;
};

struct lst{
   struct lst *next;
   struct table *data;
};

when I’m trying to assign a name like

l->data->name = d->name;
printf(“%s”,l->data->name);

it gives segmentation fault. So is it because read-only memory or caused by another reason ?

ok I solved the problem : )
I’ve done :

l->data = d;
d has the name already 🙂 thanks all

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:36:46+00:00Added an answer on May 13, 2026 at 6:36 am

    Just before you do that segmentation-violation-causing instruction, insert:

    printf( "%p\n", l);
    printf( "%p\n", l->data);
    printf( "%p\n", d);
    printf( "%p\n", d->name);
    

    and see which one is set to NULL (or an invalid value).

    Your segmentation violation is almost certainly caused by an uninitialized pointer.

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