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Asked: 2026-05-11T12:04:40+00:00

I have two subsequent mysqli statements, and the second returns: Fatal error: Call to

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I have two subsequent mysqli statements, and the second returns:

Fatal error: Call to a member function bind_param() on a non-object in …

Why this happens? Does this means that I need to open two different connection? Is there any way to avoid this (I love keeping the SQL connection details in one file)?

Here the code:

$db = new mysqli('localhost', 'root', '', 'database');  $stmt = $db->prepare('UPDATE posts SET vote_'.$_POST['vote'].' = vote_'.$_POST['vote'].' + 1 WHERE id=?'); $stmt->bind_param('s', $_POST['id_post']); $stmt->execute(); $stmt->close();  $stmt = $db->prepare('INSERT INTO votes (kind, users_id, posts_id) VALUES (?, ?, ?)'); $stmt->bind_param('sss',$_POST['vote'],$_POST['id_user'],$_POST['id_post']); $stmt->execute(); $stmt->close();
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1 Answer

  1. Check the return value of mysqli::prepare. If it is FALSE, you should get the details for the occured error with mysqli::error.

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