Question

I have two succeeding function with the same condition and I wonder what is the best way to write this? I know the one way to do this is using if (condition) … end, but I’m wondering if I can do it in one-line similar to bash, ‘[$n == $value] echo “$n” && break’.

n = 0
loop do
  puts n if n == value # puts and break is having the same condition, but
  break if n == value # can we do it in one line?
  n += 1
end

Answer 1

One easy way is to just parenthesize the statements:

ruby-1.9.1-p378 > 0.upto(5) do |n|
ruby-1.9.1-p378 >     (puts n; break;) if n == 3
ruby-1.9.1-p378 ?>    puts ">>#{n}<<"
ruby-1.9.1-p378 ?>  end
>>0<<
>>1<<
>>2<<
3

If it’s a bit much to put in parentheses, a begin-end will do the trick:

0.upto(5) do |n|
  begin
      puts "I found a matching n!"
      puts n
      puts "And if you multiply it by 10, it is #{10*n}"
      break;
  end if n == 3
  puts "((#{n}))"
end

Output:

((0))
((1))
((2))
I found a matching n!
3
And if you multiply it by 10, it is 30