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Home/ Questions/Q 6066151
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T09:28:12+00:00 2026-05-23T09:28:12+00:00

I have two table employee table and employee dependency table. Employee tooks like below.

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I have two table employee table and employee dependency table.
Employee tooks like below.

insert into E values(1,'Adam')
insert into E values(2,'Bob')
insert into E values(3,'Candy')
insert into E values(4,'Doug')
insert into E values(5,'Earl')
insert into E values(6,'Fran')

Employee dependency table looks like below

insert into Ed values(3,'2')
insert into Ed values(3,'5')
insert into Ed values(2,'1')
insert into Ed values(2,'4')
insert into Ed values(5,'6')

I need to find the dependency list like below

Eid  Ename     Dname
3     Candy    Bob,Fran

Please help me finding the above.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T09:28:12+00:00Added an answer on May 23, 2026 at 9:28 am

    Setup:

    create table E(id int , name varchar(100))
    
    insert into E values(1,'Adam')
    insert into E values(2,'Bob')
    insert into E values(3,'Candy')
    insert into E values(4,'Doug')
    insert into E values(5,'Earl')
    insert into E values(6,'Fran')
    
    create table Ed(id1 int, id2 int)
    
    insert into Ed values(3,2) 
    insert into Ed values(3,5)
    insert into Ed values(2,1)
    insert into Ed values(2,4)
    insert into Ed values(5,6)
    

    Query:

    select Name,
        stuff((select ',' + e1.name
        from Ed
            join E e1 on
                Ed.id2 = e1.id
        where Ed.id1 = E.id
        for xml path('')), 1, 1, '') as Dependents
    from E
    

    Result:

    Name       Dependents
    ---------- --------------
    Adam       NULL
    Bob        Adam,Doug
    Candy      Bob,Earl
    Doug       NULL
    Earl       Fran
    Fran       NULL
    

    If you need to show only those that have dependents:

    select *
    from
    (
        select Name,
            stuff((select ',' + e1.name
            from Ed
                join E e1 on
                    Ed.id2 = e1.id
            where Ed.id1 = E.id
            for xml path('')), 1, 1, '') as Dependents
        from E
    ) tt
    where Dependents is not null   
    
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