Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7667371
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T15:05:08+00:00 2026-05-31T15:05:08+00:00

I have two tables 1 and 2 or i need this result ( see

  • 0

I have two tables 1 and 2 or i need this result (see my image 1) using Join in mysql also see my Query for verification

  SELECT c.`id`, 
         c.`name`, 
         COUNT(*) AS `totalcount`
    FROM categories c INNER JOIN subcategories sc 
            ON c.`id` = sc.`cat_id`
GROUP BY c.`id`
ORDER BY c.added_date DESC

I want this result

enter image description here

Table 1

enter image description here

Table 2

enter image description here

Help are definitely appreciated

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-31T15:05:10+00:00Added an answer on May 31, 2026 at 3:05 pm

    USE LEFT JOIN instead of INNER JOIN

    try this:

    SELECT a.`id`, a.`name`, count(b.`cat_id`) as totalCount
    FROM categories a LEFT JOIN subcategories b
            on a.id = b.cat_ID
    GROUP BY a.`id`
    ORDER BY a.added_date desc
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a mysql problem. I have two tables like this that I need
I am newbee with PHP and MySQL and need help... I have two tables
Ive got a problem with a MySQL query. Let's say, we have two tables:
I have two tables : teachers (teacher_id,teacher_name) courses (teacher_id,course_id) And I need to display
I have two tables with a weak relation. I need get a text value
I have two tables like the ones below. I need to find what exchangeRate
I have two tables: Campaigns, Campaign_statistics. I need to output campaigns list with nested
I have two different tables from which I need to pull data blogs which
I have a two tables that are Subject and chapter . I need to
1I have the following two tables (sample data) and need to be able to

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.