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Home/ Questions/Q 8696123
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T01:12:22+00:00 2026-06-13T01:12:22+00:00

I have two tables A and B , A referred to B by field

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I have two tables A and B, A referred to B by field A.id_b B.id, so that any id_b value present in B.id.

I have three queries:
First one:

SELECT COUNT(b.id)
FROM B b
WHERE b.id NOT IN (
    SELECT a.id_b
    FROM A a)

It gives me 0;

Second one, difference only in NOT:

SELECT COUNT(b.id)
FROM B b
WHERE b.id IN (
    SELECT a.id_b
    FROM A a)

This query gives me: 1899

Third one:

SELECT COUNT(b.id)
FROM B b

And this query gives me 3599

SAME result in:

SELECT a.id_b
FROM A a

guaranty me spliting B.id on two sets, and count of elements in both sets must much total elements count, but I have: 1899 + 0 != 3599.

How that could be?

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  1. Editorial Team
    Editorial Team
    2026-06-13T01:12:23+00:00Added an answer on June 13, 2026 at 1:12 am

    Found the reason. There was records in A, which has NULL values in A.id_b. That’s why query:

    SELECT COUNT(b.id)
    FROM B b
    WHERE b.id NOT IN (
        SELECT a.id_b
        FROM A a)
    

    was returning 0.

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