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Home/ Questions/Q 811445
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T01:02:49+00:00 2026-05-15T01:02:49+00:00

I have two tables A,B which are related to each other (simplified): A: +——-+———+

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I have two tables A,B which are related to each other (simplified):

A:
+-------+---------+ 
| id    | type    | 
+-------+---------+ 
| 1     | apple   | 
| 2     | orange  | 
| 3     | banana  | 
+-------+---------+ 

B:
+-------+---------+-----------+ 
| id    | a_id    |  rank     |  
+-------+---------+-----------+  
| 1     | 1       |  9.9      |
| 2     | 1       |  7.7      |
| 3     | 2       |  3.3      |
| 4     | 2       |  8.8      |
| 5     | 2       |  1.1      |  
| 6     | 3       |  3.3      |
| 7     | 3       |  2.2      | 
| 8     | 1       |  0.0      | 
+-------+---------+-----------+   

What mysql query will return the following result?

Result
+-------+---------+-----------+ 
| id    | type    |  rank     |  
+-------+---------+-----------+  
| 1     | apple   |  0.0      | 
| 2     | orange  |  1.1      | 
| 3     | banana  |  2.2      | 
+-------+---------+-----------+ 

The rank that was inserted last in table B is picked (it’s not MAX(rank)).

The rank in the result table needs to be picked from table B with the highest id.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T01:02:49+00:00Added an answer on May 15, 2026 at 1:02 am

    UPDATED

    You may want to try joining with a subquery to get the MAX(id) for each a_id in table_b, and then INNER JOIN with table_b to get the rank:

    SELECT   ta.id, 
             ta.type,
             tb.rank
    FROM     table_a ta
    JOIN     (
                SELECT   MAX(id) AS id, 
                         a_id
                FROM     table_b
                GROUP BY a_id
             ) sub_q ON (sub_q.a_id = ta.id)
    JOIN     table_b tb ON (tb.id = sub_q.id)
    ORDER BY ta.id;
    

    Test case:

    CREATE TABLE table_a (id int, type varchar(10));
    CREATE TABLE table_b (id int, a_id int, rank decimal(2,1));
    
    INSERT INTO table_a VALUES (1, 'apple');
    INSERT INTO table_a VALUES (2, 'orange');
    INSERT INTO table_a VALUES (3, 'banana');
    
    INSERT INTO table_b VALUES (1, 1, 9.9);      
    INSERT INTO table_b VALUES (2, 1, 7.7);       
    INSERT INTO table_b VALUES (3, 2, 3.3);       
    INSERT INTO table_b VALUES (4, 2, 8.8);      
    INSERT INTO table_b VALUES (5, 2, 1.1);         
    INSERT INTO table_b VALUES (6, 3, 3.3);       
    INSERT INTO table_b VALUES (7, 3, 2.2);       
    INSERT INTO table_b VALUES (8, 1, 0.0);      
    

    Result:

    +------+--------+------+
    | id   | type   | rank |
    +------+--------+------+
    |    1 | apple  |  0.0 |
    |    2 | orange |  1.1 |
    |    3 | banana |  2.2 |
    +------+--------+------+
    3 rows in set (0.01 sec)
    
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