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Home/ Questions/Q 3402646
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T05:09:49+00:00 2026-05-18T05:09:49+00:00

I have two tables applications and leads application table submitDate | fName | lName

  • 0

I have two tables applications and leads

application table

submitDate | fName | lName
2010-11-15    joe    smith
2010-11-16    joe    smith
2010-11-15    joe    smith

Leads table

submitDate | click | state
2010-11-15    1      ca
2010-11-16    1      ca
2010-11-16    1      ca
2010-11-15    1      ca
2010-11-15    1      ca
2010-11-15    1      ca
2010-11-15    1      ca
2010-11-15    1      ca

I want a query to return this result

submitDate | application | clicks | percent
2010-11-15    2            6          33%
2010-11-16    1            2          50%

I tried the following

SELECT `submitDate` , count(`submitDate`)  AS 'comp',(select sum(`click`) from `leads`

 WHERE `submitDate` between '2010-11-15' AND '2010-11-16' group by `submitDate`)as

 'clicks'  from `applications` WHERE `submitDate` between '2010-11-15' AND

 '2010-11-16' group by `submitDate`

this return an error

#1242 - Subquery returns more than 1 row

and tried the following

SELECT `leads`.`submitDate` , count(`leads`.`submitDate`) 
 AS 'application',sum(`click`) as 'clicks'  
from `applications`,`leads` WHERE `leads`.`submitDate` between 
'2010-11-15' AND '2010-11-16' group by `leads`.`submitDate`

this return the following result

submitDate | application | clicks
2010-11-15    60           60
2010-11-16    6            6

leads table have 22 columns / 20 = 2010-11-15 and 2 2010-11-16
the application table as same as the above table

I’m sorry for the long explination but to be clear

any idea?

and about add new field percent that devided applications/leads
SO the result will have 4 columns

thanks in advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T05:09:50+00:00Added an answer on May 18, 2026 at 5:09 am
    select d.date, coalesce(a.count, 0) as applications, coalesce(b.count, 0) as clicks
    from 
    (
        select date from applications
        union
        select date from leads
    ) d
    left outer join (
        select date, count(*) as count
        from applications 
        group by date
    ) a on d.date = a.date
    left outer join (
        select date, count(*) as count
        from leads
        group by date
    ) b on d.date = b.date
    
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