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Home/ Questions/Q 4031240
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:34:21+00:00 2026-05-20T11:34:21+00:00

I have two tables: contactGroups cg and contactGroupLink cgl . CREATE TABLE `contactgroups` (

  • 0

I have two tables:

contactGroups cg and contactGroupLink cgl.

CREATE TABLE `contactgroups` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `account` int(11) DEFAULT NULL,
  `name` varchar(50) DEFAULT NULL,
  `description` text,
  `dateCreated` datetime DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=2 DEFAULT CHARSET=latin1

CREATE TABLE `contactgrouplink` (
  `groupId` int(11) NOT NULL,
  `ContactId` int(11) NOT NULL,
  PRIMARY KEY (`groupId`,`ContactId`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1

If a contact is in a group then an entry gets put into the cgl table with the contactId and the groupId.

This all works fine.

I am wanting to do a query that gets all information for all groups from the cg table where account = 1.

As part of this query I also want to add an extra row called number which has the number if entries in the cgl table for that group.

I am using

SELECT
  cg.id AS id,
  NAME,
  description,
  dateCreated,
  COUNT(*) AS number
FROM 
  contactgroups cg,
  contactgrouplink cgl
WHERE 
  cg.account = 1
AND 
  cg.id = cgl.groupId
GROUP BY
  cg.id

Which works perfect as long as at least one contact exists for a group.
otherwise the group is not returned.

What must I do to this query to make it return all groups?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:34:22+00:00Added an answer on May 20, 2026 at 11:34 am

    Use a LEFT JOIN to return a row for every member of the left table, even if there is no corresponding row in the right table.

    In other words, use this query:

    SELECT
      cg.id AS id,
      NAME,
      description,
      dateCreated,
      COUNT(cgl.groupId) AS number
    FROM contactgroups AS cg
    LEFT JOIN contactgrouplink AS cgl
    ON cg.id = cgl.groupId
    WHERE cg.account = 1
    

    Of course this will only return all groups where cg.account = 1, but I assume that is what you meant by “all groups”. (If you really want all groups, then omit the WHERE clause).

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