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Home/ Questions/Q 8239635
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T20:12:59+00:00 2026-06-07T20:12:59+00:00

I have two tables in MySQL, (and using PHP) which look similar to below:

  • 0

I have two tables in MySQL, (and using PHP) which look similar to below:

------------------------       
|                      |
|        sizes         |   <--- This table is what populates the Select Box
|                      |
------------------------
|    id     |   name   |
|           |          |           
|     1     |   Small  |
|     2     |   Medium |
|     3     |   Large  |
------------------------

----------------------------------------       
|                                      |
|            user_entries              | <--- This table relates to above by "size_id"
|                                      |
----------------------------------------
|    id     |   user_id  |   size_id   |
|           |            |             |
|     1     |     25     |      2      |
|     2     |     12     |      3      |
|     3     |     15     |      3      |
----------------------------------------

My question is: How can I write my SELECT statement to both populate a select box with all the size options (Small, Med, Large) AND pre-select the option based on the user’s preference.

For example, for the user with user_id=25, the HTML would look like:

<select>
   <option>Small</option>
   <option selected="selected">Medium</option>
   <option>Large</option>
</select>
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  1. Editorial Team
    Editorial Team
    2026-06-07T20:13:00+00:00Added an answer on June 7, 2026 at 8:13 pm

    SQL is:

    SELECT s.id, s.name, ue.id as UserSelected
      FROM sizes s
        LEFT JOIN user_entries ue ON s.id=ue.size_id AND ue.user_id=XXX
      ORDER BY s.id 
    

    (Set the order as you want)

    The, when you run through the results, if “UserSelected” is not NULL (i.e. has a value) then you have the selected entry.


    SQL tips: try to keep column names the same between tables, so that “size_id” is the name of the id field in the size table as well as the foreign key in user_entries table; this way, you wouldn’t have two “id” columns in this query that would cause problems.

    You also probably don’t need the “id” column in the user_entries table as you’ll always search/update based on user_id? Just one less column/index to handle if you don’t need it.

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