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Home/ Questions/Q 6215393
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T07:02:53+00:00 2026-05-24T07:02:53+00:00

I have two tables table TA(id, name_A) and Table TB(id, name_B). they are many

  • 0

I have two tables

    table TA(id, name_A) and 
    Table TB(id, name_B).

they are many to many relation. so I create a third table

    TA_TB(id, A_id, B_id)

with appropriate foreign keys. Now I execute these queries to insert the data into mysql which fails.

    $cat = $_POST["cat"];
    $B_list=$_POST["B_list"];
if ($B_list){
  foreach ($B_list as $i)
  {
    $query = "insert into TA_TB(A_id, B_id) values((select id from Table_A where name_A like '$cat'), (select id from Table_B where name_B like '$i'))";
    if (!$query) {
          die('Could not add Item:' . mysql_error());
          break;
        }
      }

}

what is going wrong here? I know the values are coming in fine, because I can get them echoed or printed on the page alright. Insert does not insert. something is going wrong.

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  1. Editorial Team
    Editorial Team
    2026-05-24T07:02:53+00:00Added an answer on May 24, 2026 at 7:02 am

    You need to use the mysql_query() function:

    $query = mysql_query("insert into TA_TB(A_id, B_id) values((select id from Table_A where name_A like '$cat'), (select id from Table_B where name_B like '$i')))";
    

    Otherwise you just have a string.

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