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Home/ Questions/Q 6757591
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:40:17+00:00 2026-05-26T13:40:17+00:00

I have two tables. The first is subscribers. Subscribers are also appointed to a

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I have two tables. The first is subscribers. Subscribers are also appointed to a category. The second table is payments that the subscribers made. I want to know what the average time is between the time of subscription and the FIRST payment of a subscriber (the can make multiple).

Here is a piece of SQL, but it doesn’t do what I want just yet – although I have the feeling I’m close 😉

SELECT category,
AVG(TIMESTAMPDIFF(HOUR, subs.timestamp, MIN(payments.timestamp)))
FROM subs
JOIN payments ON (payments.user_id = subs.user_id)
GROUP BY category

Now I get “Invalid use of group function” – because of the MIN function, so that ain’t right. What do I have to do now? Thanks in advance!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:40:18+00:00Added an answer on May 26, 2026 at 1:40 pm
    SELECT category,
    AVG(TIMESTAMPDIFF(HOUR, subs.timestamp, p.timestamp))
    FROM subs
    JOIN ( SELECT user_id
                , min(timestamp) timestamp
             FROM payments 
           GROUP BY user_id
         ) p
    ON p.user_id = subs.user_id
    GROUP BY category
    

    If you needed to update another table with the results of this query, you could do something like this (not tested, so there may be syntax errors but hopefully you get the idea). I assume that another_table has category and avg_hrs_spent columns.

    UPDATE another_table
       SET avg_hrs_spent =
         (
           SELECT a.avg_hrs_spent FROM
           (
             (SELECT category,
                     AVG(TIMESTAMPDIFF(HOUR, subs.timestamp, p.timestamp)) avg_hrs_spent
                FROM subs
                JOIN ( SELECT user_id
                            , min(timestamp) timestamp
                         FROM payments 
                       GROUP BY user_id
                   ) p
                ON p.user_id = subs.user_id
                GROUP BY category) a
           )
           WHERE a.category = another_table.category
         )
    
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