Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4112800
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T22:14:30+00:00 2026-05-20T22:14:30+00:00

I have two tables. The name table have a foreign key named ‘categories’. The

  • 0

I have two tables. The name table have a foreign key named ‘categories’. The other table is ‘categories’ that contains name of the categories. The name table references a category in the categories table.

So I use this:

$categories = "SELECT name, COUNT(*) category";
$number_of_categories = "SELECT category, COUNT(1) FROM name GROUP BY category";

As you can see, I’m doing two select statements. I heard that joining tables can do magic, please teach me how to do this in one SELECT statement.

Basically I want to SELECT all the rows from the category table, and then count the number of instances of each category in the name table.

  • 1 1 Answer
  • 1 View
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-20T22:14:31+00:00Added an answer on May 20, 2026 at 10:14 pm
    SELECT c.name, COUNT(n.category) AS count_in_name_table
    FROM categories c
    LEFT JOIN name n ON n.category = c.name
    GROUP BY c.name
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have two tables that have a foreign key constraint between them Table event
I have two tables, Subject and Content, where Content references Subject with foreign key.
For example, I have two tables. Name: Customer Primary key: idCustomer AnotherColumn: name Foreign
I have two tables named MEMBER - columns id(primary key), name, email & TOPICS
I have two tables: DRIVER(Driver_Id,First name,Last name,...); PARTICIPANT IN CAR ACCIDENT(Participant_Id,Driver_Id-foreign key,responsibility-yes or no,...).
I have two tables one with ID and NAME table 1 ID | NAME
Quick method description: I have two tables, lets name them table ONE and table
I have Two tables. 1.Users table (Username , Name) 2.Picture table( ID , Username
I have two tables: Table items: | id | name | description | |
I have two tables user table user_id | name | 1 | peter |

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.