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Home/ Questions/Q 8484683
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T20:26:48+00:00 2026-06-10T20:26:48+00:00

I have two tables with a FK relation. What I want is equivalent to:

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I have two tables with a FK relation. What I want is equivalent to:

select A.*, B.*
from A
join B
    on B.A_ID = A.ID

How do I do this efficiently in jOOQ? In the end, I need one instance of ARecord and one of BRecord per resulting row.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T20:26:50+00:00Added an answer on June 10, 2026 at 8:26 pm

    Like this

    Result<Record> result =
    create.select()
          .from(A)
          .join(B).on(B.A_ID.equal(A.ID))
          .fetch();
    

    This will fetch A.*, B.* (or more precisely, A.A1, A.A2, ..., A.AN, B.B1, ...). Now in order to transform result into ARecord and BRecord use the Result.into(Table) method:

    ARecord a = result.into(A);
    BRecord b = result.into(B);
    

    Note, that this has known flaws. For instance, if A.X is a field that has a corresponding field B.X (same field name), A.X will hold B.X‘s value. I have registered a bug report for this: #1802

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