Question

I have two tabs named respectly liste_pieces and client_pieces.

The first contain a list of many elements about 1000. the second contain some element of the first.

Actually I’m doing a query to fullfill the second tab with the first.

Also I would like to display all element from the first that are not in the second.

I’ve thought I could do a joint pas a joint will only display elements that are in both tab.

And actually that is not what I’m looking for.

I’ve done that query for the moment

      <table id="box-table-a" width="100%">
    <tr>
        <th scope="col" width="50%">LISTE DES PI&Egrave;CES</th>
        <th scope="col" width="50%">AJOUT ?</th>
    </tr>

<?php $sql="SELECT * FROM `liste_pieces`";
$result=mysql_query($sql) or die;$i=0;
while($data=mysql_fetch_assoc($result))

{?>
<tr>
    <td><?php echo $data['libelle'] ; ?></td>
    <td style="text-align:center" align="center">
  <p align="center">  <input type="hidden" name="piece[<?php echo $i ; ?>]" value="0" /><input type="checkbox" class="checkbox" value="1" name="piece[<?php echo ++$i ; ?>]" id="piece[<?php echo ++$i ; ?>]" /></p></td>

</tr>
<?php } ?>

But this display to me all elements from the first tab. I do not really know how to remove elements that exists in the second tab.

I have the column id on liste_pices that is the same in the second tab except that it is called id_piece.

I’m a bit lost.

I do not know how to process.

Receive All my utmost Respect.

Kind regards.

SP.

Answer 1

Use queries like this

"select * from liste_pieces where column_name not IN (select column_name from client_pieces)"

and

"select * from client_pieces where column_name not IN (select column_name from liste_pieces )"

This will solve your problem, the column_name should present in both table with same datatype.