Question

I have two vectors of MyObj structs. MyObj is defined as follows:

struct MyObj
{
   float x, y;
   unsigned int data[8];
   unsigned int tmp[1];

   MyObj(const MyObj &m) 
   {
      x = m.x; y = m.y; 
      tmp[0] = 0;
      for (int i = 0; i < 8; ++i)
      {
         data[i] = m.data[i];
      }
   }
};

I then have two vectors…

vector<MyObj> v1; 
vector<MyObj> v2;
// both get data eventually.

v1.insert(v1.end(), v2.begin(), v2.end());

v2 has 3535004 elements in my experiment. v1 is similarly sized. I’ve also tried building a new vector and just using .push_back to build it from both vectors.

Essentially, when I try to merge the two vectors I just get an error from visual studio saying “Debug error! R6010, abort() has been called”. Very non-useful…

So my question is: what could be causing this error, and how can I solve it? Thank you

Answer 1

vtext.cpp:

#include <vector>
#include <iostream>
using namespace std;

struct MyObj
{
   float x, y;
   unsigned int data[8];
   unsigned int tmp[1];

   MyObj() {}
   MyObj(const MyObj &m) 
   {
      x = m.x; y = m.y; 
      tmp[0] = 0;
      for (int i = 0; i < 8; ++i)
      {
         data[i] = m.data[i];
      }
   }
};

int main(void)
{
    vector<MyObj> v1(3535004); 
    vector<MyObj> v2(3535004);
    // both get data eventually.

    v1.reserve(3535004 + 3535004);

    cout << v1.capacity() << endl;

    v1.insert(v1.end(), v2.begin(), v2.end());

    cout << "It worked" << endl;
}

$ g++ vtest.cpp -o vtest

$ ./vtest

7070008

It worked

It worked with and without the reserve statement. Either you are working on a very low memory system (mine has 4GB) or the error is in something you haven’t shown us.

Edit: Following @MooingDuck’s implied suggestion in his comment, if you still have problems replace the insert statement above with

try 
{
        v1.insert(v1.end(), v2.begin(), v2.end());
}
catch (exception& e)
{
   cout << e.what() << endl;
}

and take it from there. Also add #include <exception> at the top.