I have two views in a RelativeLayout, both of which fill the screen, so view B is on top of view A. I also have an animation defined which can move view B partially offscreen to show view A underneath. The animation works fine, but I’m having the classic issue of the view bounds not moving with the view, so the button that I use to trigger the animation (which is located on view B) is only clickable from its original position, no matter where view B is located. The issue that I’m having is that after the animation ends, when I set the layout params it’s causing view B to be redrawn again, translated from the location of the end of the animation.
As a concrete example, the left edge of view B is initially at x = 0, with a button at x = 450. When the button is pressed, an animation moves the view to x = -400. This works properly – the view is partially off the left hand side of the screen, and the button is now at x = 50, so it is still on screen. The click area for the button though is still at x = 450. So now I set the layout params on view B:
RelativeLayout.LayoutParams lp = (RelativeLayout.LayoutParams) viewB.getLayoutParams();
lp.rightMargin = 400;
viewB.setLayoutParams(lp);
Once the new params are set, the view gets 400px of padding on the right, moving the entire view to x = -800. The clickable area for the button is now properly at x = 50 though, so it seems like I can have it look right or act right. Any idea what I’m doing wrong? Here’s how the animation is set up.
Animation anim = null;
anim = new TranslateAnimation(0, -400, 0, 0);
anim.setAnimationListener(this);
anim.setDuration(duration);
viewB.startAnimation(anim);
I was able to get things working by changing the layout params before or after the animation, as appropriate: