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Home/ Questions/Q 8016197
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T20:28:31+00:00 2026-06-04T20:28:31+00:00

I have used json_decode to get an array from a JSON response: $result =

  • 0

I have used json_decode to get an array from a JSON response:

$result = (json_decode($trends,true)); 

which gives me the following (I haven’t included all of the EstablishmentDetail array results)

Array ( [FHRSEstablishment] => Array ( [Header] => Array ( [#text] => [ExtractDate] => 2012-05-28 [ItemCount] => 5 [ReturnCode] => Success ) [EstablishmentCollection] => Array ( [EstablishmentDetail] => Array ( [0] => Array ( [FHRSID] => 248659 [LocalAuthorityBusinessID] => INS/06/06179 [BusinessName] => Ancient Raj [BusinessType] => Restaurant/Cafe/Canteen [BusinessTypeID] => 1 [AddressLine1] => 26 North Lane, Canterbury, [PostCode] => CT2 7EE [RatingValue] => 3 [RatingKey] => fhrs_3_en-GB [RatingDate] => 2010-11-18 [LocalAuthorityCode] => 180 [LocalAuthorityName] => Canterbury City [Scores] => [SchemeType] => FHRS [Geocode] => )

which I thought I’ be able to use a foreach to get to the BusinessName:

foreach ($result->FHRSEstablishment->EstablishmentCollection->EstablishmentDetail as $detail){
    echo $detail['BusinessName'];
}

but I’m not getting any results.

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  1. Editorial Team
    Editorial Team
    2026-06-04T20:28:32+00:00Added an answer on June 4, 2026 at 8:28 pm

    The problem is that you’re accessing your $result as an object:

    $result->FHRSEstablishment
    

    but when you’re calling json_decode with the second parameter set to true, it’s returning an associative array, which you should access as:

    $result['FHRSEstablishment']['EstablishmentCollection'] //...
    

    If you want to be able to access your $result with object notation, you should define it as:

    $result = json_decode($trends) //without 2nd parameter = true
    
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