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Home/ Questions/Q 8704919
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T03:13:49+00:00 2026-06-13T03:13:49+00:00

I have used spring validation in the conventional way like this: @RequestMapping(value=userRegistration, method =

  • 0

I have used spring validation in the conventional way like this:

@RequestMapping(value="userRegistration", method = RequestMethod.POST)
public ModelAndView registerUser(@Valid UserAccountVO userAccountVO, BindingResult result,Model model){
    if (result.hasErrors()){
    // Do something
    }
//Do something else
}

That works well and good.

But now I have case where I can’t do a form submission, but instead get values in javascript and send them using Ajax on click of a button, something like this.

var nameStr = $("#usrnmbx").val();
var emailidStr = $("#emailidbx").val()
//and more and then send them using ajax

So to implement bean validation my new method looks something like this.

@RequestMapping(value = "/userRegistration", method = RequestMethod.POST)
public @ResponseBody JSONresponse registerUser(HttpServletRequest request,@RequestParam(value = "name") String name, // and more){

UserAccountVO userAccountVO = new UserAccountVO(name, emailId,password, confirmPassword);
BindingResult result = new BeanPropertyBindingResult(userAccountVO,"userAccount");
userAccountValidator.validate(userAccountVO, result); //userAccountValidator is spring Validator implementation 
if (result.hasErrors()) {
 //Do something
}
//Do something else
}

But this looks dirty. I definitely think there are better ways of doing this. And this doesn’t seem like picking up the validation annotations that I have put up in the POJO.
Can any of you suggest a better implementation.
Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-13T03:13:50+00:00Added an answer on June 13, 2026 at 3:13 am

    you can submit whole form with ajax. In this case your command object should be populated as ordinary form submission.

    here is my aproach

            function submitAjaxForm(form, url) {  
            $.post(url, $(form).serialize(),function(data) {
                  ...........
                }); 
    }
    
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