Question

I have used this web link as reference.

The following code is generating this debug error:

I am unable to find the bug. Please help me.

#include <stdio.h>
#include <stdlib.h>
#include <process.h>

#define ROWS 3
#define COLS 5

main()
{
    char ** my2dArray = NULL;
    int i=0;
    int j=0;

    my2dArray = (char**) malloc(sizeof(char) * ROWS);

    for(i=0 ; i<ROWS ; i++)
    {
        my2dArray[i] = (char*) malloc(sizeof(char) * COLS);
    }

    for(i=0 ; i<ROWS ; i++)
    {
        for(j=0 ; j<COLS ; j++)
        {
            my2dArray[i][j] = (i + 1) * (j + 1);
        }
    }

    for(i=0 ; i<ROWS ; i++)
    {
        for(j=0 ; j<COLS ; j++)
        {
            printf("%d, ", my2dArray[i][j]);
        }

        printf("\n");
    }

    for(i=0 ; i<ROWS ; i++)
    {
        free(my2dArray[i]);
    }

    free(my2dArray);

    system("PAUSE");
}

Answer 1

You are storing items of type char* in my2dArray[i]:

my2dArray[i] = (char*) malloc(sizeof(char) * COLS);

char is 1 byte, char* is 4 or 8 byte, so you’re not allocating enough memory for my2dArray at the moment, change it to this:

my2dArray = (char**) malloc(sizeof(char*) * ROWS);