Question

I Have used URLValidator class in java to validate URL . But I Want that if user won’t give any protocol in URL then also the validation should be returned as valid.

Explaned Correctly: If this is supplied in URL “http://www.google.com” then also it should be a valid URL and if “www.google.com” is supplied then also the validation should returned as valid URL.

I have tried a lot .Please Help me in this.
Thanks In Advance.

Answer 1

check if that works for you:

boolean foundMatch = false;
try {
    Pattern regex = Pattern.compile("\\b(?:(https?|ftp|file)://|www\\.)?[-A-Z0-9+&#/%?=~_|$!:,.;]*[A-Z0-9+&@#/%=~_|$]\\.[-A-Z0-9+&@#/%?=~_|$!:,.;]*[A-Z0-9+&@#/%=~_|$]", Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE);
    Matcher regexMatcher = regex.matcher(subjectString);
    foundMatch = regexMatcher.matches();
} catch (PatternSyntaxException ex) {
    // Syntax error in the regular expression
}